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The Symbol of an Operator

The operator $T$ discussed above does not correspond to any differential operator. Only polynomials in ${\bf k}$ correspond to differential operators, and this is via a very simple relation. The differential operator $\partial/\partial x_j$ corresponds to the symbol $(i k_j)$ since

$\displaystyle \frac{\partial}{\partial x_j} \exp ( i {\bf k} \cdot {\bf x} ) = i k_j \exp ( i {\bf k} \cdot {\bf x} ).$     (22)

From this we have,
$\displaystyle \mbox{\tt Symbol: } \sum _{\vert\gamma \vert \leq m} a_\gamma (i ...
...\tt Differential Operator: } \sum _{\vert\gamma \vert \leq m} a_\gamma D^\gamma$     (23)

where $i {\bf k} = (i k_1, \dots, i k_n ), \gamma = (\gamma _1, \dots, \gamma_n),
(i{\bf k})^\gamma = (i k_1)^{\gamma _1} \dots (i k_n)^{\gamma _n}$ and $D^\gamma =
(\partial ^{\gamma _1}/\partial x_1^{\gamma _1})\dots(\partial ^{\gamma _n}/\partial x_n^{\gamma _n})$.

For a general operator $T$, defined on functions in an infinite space, we define the symbol $\hat T({\bf k})$ by

$\displaystyle T \exp ( i {\bf k} \cdot {\bf x} ) = \hat T({\bf k}) \exp ( i {\bf k} \cdot {\bf x} ).$     (24)

This definition is for scalar PDE as well as for systems of PDE. In the second case the symbol will be a matrix whose elements are functions of ${\bf k}$. A definition in a bounded domain $\Omega$ can also be done, by considering a small vicinity of a point in $\Omega$ and a localization of the above.

Using the definition (24) we see that we can define a larger class of operators by considering symbols which are not polynomials. Under some assumptions which we omit here, one gets the class of pseudo-differential operators. They play a very important role in the study of boundary value problems for elliptic equations.



Example IV. We consider next the example

$\displaystyle \begin{array}{ll}
\Delta \phi = 0 & \Omega \\  \
\phi = \alpha & \partial \Omega
\end{array}$     (25)

where $\Omega$ is any of the two domains in the previous example. Following the same procedure as before,
\begin{displaymath}
\alpha({\bf x}) = \exp ( i {\bf k} \cdot {\bf x} )
\end{displaymath} (26)


\begin{displaymath}
\phi({\bf x} , z ) = A \exp ( i {\bf k} \cdot {\bf x} ) \exp ( \sigma z )
\end{displaymath} (27)

implies
\begin{displaymath}
\sigma ^2 - \vert {\bf k} \vert ^2 = 0
\end{displaymath} (28)

and the relevant solution is
\begin{displaymath}
\phi ({\bf x}, z) = A \exp ( i {\bf k} \cdot {\bf x} ) \exp ( - \vert{\bf k}\vert z ).
\end{displaymath} (29)

The value of $A$ is determined from the boundary condition and clearly we have
$\displaystyle A = 1.$     (30)

The relation of $\frac{\partial \phi}{\partial n}_{\vert _{\partial\Omega}}$ to the boundary values $\phi _{\vert _{\partial\Omega}}$ is described by a mapping $S$
$\displaystyle {\frac{\partial \phi}{\partial n}}_{\vert _{\partial\Omega}}= S \alpha$     (31)

whose symbol can be easily found by differentiating $\phi$ in the outward normal direction at the boundary, giving
$\displaystyle \hat S ({\bf k} ) = \vert {\bf k}\vert.$     (32)

Notice that although we are dealing with differential problems, some relation between boundary values are not governed anymore by differential operators. The operators $S,T$ from the last two examples are therefore not differential operators but pseudo-differential operators.

Shape design problems are related to boundary control problems, and therefore these type of operators play a very important role in shape optimization. They will help us to characterize the minimization problem in quantitative way that will allow the construction of very effective solvers.


next up previous
Next: Fourier Analysis For Optimization Up: On Pseudo-Differential Operators Previous: On Pseudo-Differential Operators
Shlomo Ta'asan 2001-08-22